A circular wheel comprises a ring of radius R and mass M and three spokes of mass m and length R each. The moment of inertia of the wheel about its axis passing through its centre and perpendicular to its plane is
A
(M+m4)R2
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B
(M+m)R2
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C
(M+3m)R2
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D
(M+m2)R2
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Solution
The correct option is B(M+m)R2 Moment of inertia of the wheel is I=Iring+3Ispoke=MR2+3(mR23)=(M+m)R2