A circular wire fo radius 'R' carries a current 'i'. What will be the magnetic field at its centre?

$\frac{μ_{0} i}{4 R}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{μ_{0} i}{R}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{μ_{0} i}{2 R}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{μ_{0} i}{2 π R}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$\frac{μ_{0} i}{2 R}$

Solution is in the next video.

Suggest Corrections

Similar questions

Q. A semicircular wire fo radius 'R' carries a current 'i'. What will be the magnetic field strength at its centre?

Q. A long straight wire of radius R carries current

i

. The magnetic field inside the wire at distance r from its centre is expresses as:

Q. A circular coil of radius

R

carries a current

i

. The magnetic field at its centre is

B

. The distance from the centre on the axis of the coil where the magnetic field will be

B / 8

Q. A circular coil of radius ‘r’ carries a current I. At what distance from centre on its axis the magnetic field is

\frac{1}{27} t h

of its value at the centre?

A circular loop of radius r carries a current i. How should a long, straight wire carrying a current, 4i be placed in the plane of the circle so that the magnetic field at the centre becomes zero ?

Join BYJU'S Learning Program

A circular wire fo radius 'R' carries a current 'i'. What will be the magnetic field at its centre?

The correct option is C μ0i2R Solution is in the next video.

The correct option is C
$\frac{μ_{0} i}{2 R}$

Solution is in the next video.