Question

A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole if the angle made by the rope with the ground level is ${30}^{\circ }$ [1 MARK]

Answer 1

Let AB be the vertical pole and CA be the 20 m long rope such that its one end is tied from the top of the vertical pole AB and the other end C is tied to a point C on the ground.



In $\Delta ABC$, we have

$sin{30}^{\circ }=\frac{h}{20}$ [$\frac{1}{2}$ MARK]

$\Rightarrow \frac{1}{2}=\frac{h}{20}$

$\Rightarrow h=10m$ [$\frac{1}{2}$ MARK]

Hence, the height of the pole is 10 m.