Question

A circus artist is climbing a 20m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. The height of the pole is

___
m if the angle made by the rope with the ground level is ${30}^{\circ }$ ^.

Answer 1

Angle of elevation $\theta$ = ${30}^{\circ }$

$\Rightarrow$ Sin$\theta$ = $\frac{perpendicular}{hypotenuse}$

$\Rightarrow$ Sin${30}^{\circ }$ = $\frac{1}{2}$ = $\frac{heightofpole}{20}$

Thus, height of pole = 10 m.