Question

A circus artist is climbing a 20m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground.
The height of the pole is ___ if the angle made by the rope with the ground level is ${30}^{\circ }$.

Answer 1

$Angleofelevation\theta ={30}^{\circ }$

$\Rightarrow \sin \theta =\frac{perpendicular}{hypotenuse}$

$\Rightarrow \sin {30}^{\circ }=\frac{1}{2}=\frac{heightofpole}{20}$

$\text{Thus, height of pole = 10 m.}$