Question

A circus artist is climbing a 20m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. The height of the pole is ___ (in m)

if the angle made by the rope with the ground level is ${30}^{\circ }$ ^.

Answer 1

Angle of elevation $\theta ={30}^{\circ }$

$\Rightarrow \sin \theta =\frac{\text{perpendicular}}{\text{hypotenuse}}$

$\Rightarrow \sin {30}^{\circ }=\frac{1}{2}=\frac{\text{height of pole}}{20}$

Thus, height of pole = 10 m