Question

A circus artist is climbing a 20m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. The height of the pole is

___meter.
If the angle made by the rope with the ground level is ${30}^{\circ }$ ^.

Answer 1

Angle of elevation $\theta$ = ${30}^{\circ }$

$\Rightarrow sin\theta =\frac{perpendicular}{hypotenuse}$

$\Rightarrow sin{30}^{\circ }=\frac{1}{2}=\frac{heightofpole}{20}$

Thus, height of pole = 10 m.