A circus artist is climbing a 20m long rope which is tightly stretched and tied from the top of a vertical pole to the ground. If the rope makes an agle of $30^{\circ}$ with the ground, then the height of the pole is ___ metres.

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Solution

Angle of elevation $θ$ = $30^{\circ}$

$\Rightarrow$ sin $θ$ = $\frac{p e r p e n d i c u l a r}{h y p o t e n u s e}$

$\Rightarrow$ sin $30^{\circ}$ = $\frac{1}{2}$ = $\frac{h e i g h t o f p o l e}{20}$

Thus, height of pole = 10 m.

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A circus artist is climbing a 20m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground.
The height of the pole is ___ if the angle made by the rope with the ground level is $30^{\circ}$ .

A circus artist is climbing a 20m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. The height of the pole is ___ m if the angle made by the rope with the ground level is $30^{\circ}$ .

A circus artist is climbing a 20m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. The height of the pole is

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Q. Question 1
A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is

30^{\circ}

Q. A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole if the angle made by the rope with the ground level is

30^{\circ}

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A circus artist is climbing a 20m long rope which is tightly stretched and tied from the top of a vertical pole to the ground. If the rope makes an agle of 30∘ with the ground, then the height of the pole is ___ metres.

Angle of elevation θ = 30∘ ⇒ sinθ = perpendicularhypotenuse ⇒ sin30∘ = 12 = height of pole20 Thus, height of pole = 10 m.

A circus artist is climbing a 20m long rope which is tightly stretched and tied from the top of a vertical pole to the ground. If the rope makes an agle of $30^{\circ}$ with the ground, then the height of the pole is ___ metres.

Angle of elevation $θ$ = $30^{\circ}$

$\Rightarrow$ sin $θ$ = $\frac{p e r p e n d i c u l a r}{h y p o t e n u s e}$

$\Rightarrow$ sin $30^{\circ}$ = $\frac{1}{2}$ = $\frac{h e i g h t o f p o l e}{20}$

Thus, height of pole = 10 m.