Question

A circus artist is climbing a $20m$ long rope, which is tightly stretched and tied from the top of a vertical pole of the ground. Find the height of the pole if the angle made by the rope with the ground level is ${30}^o$

• A. 12 m
• B. 10 m
• C. 8 m
• D. 6 m

Answer 1

The correct option is B 10 m

$AC=20m$ is the length of the rope

Let $AB=h$ meters be the height of the pole

$\angle ACB={30}^o$ (Given)

Now, $△ABC$ is a right angle triangle

So,

$\sin {30}^o=\frac{AB}{AC}=\frac{1}{2}$ $\Rightarrow$ $\frac{h}{20}=\frac{1}{2}$ $\Rightarrow$ $h=10m$