A circus artist is climbing a 20m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole if the angle made by the rope with the ground level is $30^{\circ}$ .

10m

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30m

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20m

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5cm

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Solution

The correct option is A
10m

Angle of elevation $θ$ = $30^{\circ}$

$sin$ $θ$ = $\frac{p e r p e n d i c u l a r}{h y p o t e n u s e}$

$sin$ $30^{\circ}$ = $\frac{1}{2}$ = $\frac{h e i g h t o f p o l e}{20}$

Height of pole = 10m

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Similar questions

A circus artist is climbing a 20m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. if the angle made by the rope with the ground level is $30^{\circ}$ ,the height of the pole is _________ m.

Q. Question 1
A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is

30^{\circ}

Q. A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole if the angle made by the rope with the ground level is

30^{\circ}

[1 MARK]

Q. A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is

30^{\circ}

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A circus artist is climbing a 20m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole if the angle made by the rope with the ground level is 30∘.

The correct option is A 10m Angle of elevation θ = 30∘ sinθ = perpendicularhypotenuse sin 30∘ = 12 = height of pole20 Height of pole = 10m

A circus artist is climbing a 20m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole if the angle made by the rope with the ground level is $30^{\circ}$ .

The correct option is A
10m

Angle of elevation $θ$ = $30^{\circ}$

$sin$ $θ$ = $\frac{p e r p e n d i c u l a r}{h y p o t e n u s e}$

$sin$ $30^{\circ}$ = $\frac{1}{2}$ = $\frac{h e i g h t o f p o l e}{20}$

Height of pole = 10m