Question

A circus artist is climbing a 30 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. The height of the pole, if the angle made by the rope with the ground level is ${30}^{\circ }$

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m.

Answer 1

The figure above represents the given situation.
In the given figure,
$sin{30}^{\circ }=\frac{AB}{AC}\Rightarrow AB=sin{30}^{\circ }\times AC=\frac{AC}{2}=\frac{30}{2}=15m$.