Question

A circus artist is climbing a 30 m long rope, which is tightly stretched and tied from the top of a vertical pole to a point on the ground which is at a certain distance from the foot of the pole. If the angle made by the rope with the ground level is ${30}^{\circ }$, the height of the pole is ___ m.

• A. 15
• B. 10
• C. 20
• D. 30

Answer 1

The correct option is A 15


The figure above represents the given situation.
In the given figure,
$sin{30}^{\circ }=\frac{AB}{AC}\Rightarrow AB=sin{30}^{\circ }\times AC=\frac{AC}{2}=\frac{30}{2}=15m$.