A circus artist is climbing from the ground along a rope stretched from the top of a vertical pole and tied at the ground.The height of the pole is $12 m$ and the angle made by the rope with ground level is $30^{\circ} .$ Calculate the distance covered by the artist in climbing to the top of the pole.

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Solution

$sin θ = \frac{P}{H}$
$sin 30 = \frac{12}{x}$
$\frac{1}{2} = \frac{12}{x}$
$x = 24$
The artist covered $24$ m distance.

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A circus artist is climbing from the ground along a rope stretched from the top of a vertical pole and tied at the ground.The height of the pole is 12m and the angle made by the rope with ground level is 30∘. Calculate the distance covered by the artist in climbing to the top of the pole.

sinθ=PHsin30=12x12=12xx=24The artist covered 24m distance.

$sin θ = \frac{P}{H}$
$sin 30 = \frac{12}{x}$
$\frac{1}{2} = \frac{12}{x}$
$x = 24$
The artist covered $24$ m distance.