Question

A circus artist is climbing on a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. If the angle made by the rope with the ground level is 60º, then the height of the pole is

• A. 30 m
• B. $20\sqrt{3}m$
• C. 15 m
• D. $30\sqrt{3}m$

Answer 1

The correct option is B $20\sqrt{3}m$

Let the pole be OP such that rope RP makes an angle of 60° with the ground level, i.e., ∠PRO = 60°.

$In\Delta POR,$
$\tan {60}^{\circ }=\frac{OP}{RP}$
$\Rightarrow \sqrt{3}=\frac{OP}{20}$
$\Rightarrow OP=20\times \sqrt{3}=20\sqrt{3}m$
Thus, the height of the pole is
Hence, the correct answer is option (b).