A class consists of 20 boys and 30 girls. In the mid-semester examination, the average score of the girls was 5 higher than that of the boys. In the final exam, however, the average score of the girls dropped by 3 while the average score of the entire class increased by 2. The increase in the average score of the boys is
9.5
Let the average score of boys and girls be ‘b’ & ‘g’ respectively.
Given,
50×[{(30g+20b)50}+2]=30×(g−3)+20×bn, where bn is the new average score of boys.
30g+20b+100=30g−90+20bnbn=b+192(bn–b)=9.5