A class interval of a data has $15$ as the lower limit and $25$ as the size then the class mark is :

26.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

27

No worries! We‘ve got your back. Try BYJU‘S free classes today!

27.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $27.5$
Given,
Lower limit $= 15$
Size of class interval $= 25$
Upper limit $= lower limit + size = 15 + 25$ = $40$
Class mark is calculated from mean of lower and upper limit.
Class mark $= \frac{lower limit + upper limit}{2}$
$= \frac{15 + 40}{2}$
$= 27.5$

Suggest Corrections

Similar questions

Q. The lower limit and upper limit of an exclusive class interval are

15

and

25

respectively. Then the class mark is _____

Fill in the blanks :
(i) Lower class limit of 15-18 is ___ .
(ii) Upper class limit of 24-30 is ___.
(iii) Upper limit of 5-12.5 is ___.
(iv) If the upper and the lower limits of a class interval are 16 and 10; the class interval is ___.
(v) If the lower and the upper limits of a class interval are 7.5 and 12.5; the class interval is ___.

If the class mark of a class interval is 25, then the sum of its lower and upper class limits is

If 35 is the upper limit of a class interval of class size 10, then the lower limit of the class interval is _____

Class mark of a certain class interval is 30 and its lower class limit is 20. Then its upper class limit is

Join BYJU'S Learning Program

A class interval of a data has 15 as the lower limit and 25 as the size then the class mark is :

The correct option is D 27.5Given,Lower limit =15Size of class interval =25Upper limit =lower limit + size=15+25 = 40Class mark is calculated from mean of lower and upper limit. Class mark =lower limit +upper limit 2 =15+402 =27.5

A class interval of a data has $15$ as the lower limit and $25$ as the size then the class mark is :

The correct option is D $27.5$
Given,
Lower limit $= 15$
Size of class interval $= 25$
Upper limit $= lower limit + size = 15 + 25$ = $40$
Class mark is calculated from mean of lower and upper limit.
Class mark $= \frac{lower limit + upper limit}{2}$
$= \frac{15 + 40}{2}$
$= 27.5$