Question

A clock regulated by a seconds pendulum keeps correct time. During summer the length of the pendulum increases to $1.01m$. How much will the clock gain or lose in one day? $\left(g=9.8m/s^2\right)$

Answer 1

$\frac{1}{T}\frac{dT}{dL}=\frac{1}{2}\frac{1}{L}$

$dT=\left(\frac{T}{2}\times \frac{dL}{L}\right)$

$=\frac{86400}{2}\times \frac{0.01}{1}$

$dT=432\sec$