A clock with a metal pendulum beating seconds keeps correct time at 0∘C. If it loses 12.5 seconds a day at 25∘C, the coefficient of linear expansion of metal of pendulum is
A
186400per∘C
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B
143200per∘C
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C
114400per∘C
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D
128800per∘C
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Solution
The correct option is A186400per∘C Loss of time due to heating a pendulum is given as ΔT=12αΔθT⇒12.5=12×α×(25−0)∘C×86400⇒α=186400per∘C