Question

A closed box is $40$ cm long, $50$ cm wide and $60$ cm deep. Find the area of the foil needed for covering it.

Answer 1

Total surface area of cuboid = $2(lb+bh+lh)$
Given: $l=40cm$, $b=50cm$, $h$ = $60cm$
Therefore,
Total surface area of cuboid = $2$[($40$ x $50$) +($50$ x $60$) + ($60$ x $40$)] = $2[2000+3000+2400]$ = $2\left(7400\right)$

Hence the total surface area of cuboid = area of the foil needed for covering it = $14800c{m}^2$