Question

A closed bulb capacity 200ml containing ${CH}_4$, $H_2$ and He at 300K. The ratio of partial pressure of ${CH}_4$, $H_2$ and He, respectively is 2:3:5. Calculate the ratio of their weights present in the container.

• A. 2:4:6
• B. 16:8:100
• C. 16:3:10
• D. 4:9:25

Answer 1

The correct option is C 16:3:10

Partial pressure $=$ mole fraction $\times$ total pressure

$\therefore$ Mass are also in $2:3:5$

$\therefore$ Ratio of mass $=2\times 16:3\times 2:5\times 4$

$=16:3:10$