A closed circular cylinder has radius equal to $3$ cm and height $11$ cm. Find its total surface area.

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Solution

Total surface area of a cylinder with a base radius 'r' and height 'h' is given by $= T . S . A = 2 π r (h + r)$
For $r = 3 c m, h = 11 c m$
$T . S . A = 2 π (3) (11 + 3)$
$= 2 \times \frac{π}{7} \times 3 \times 14$
$= 12 \times 22 c m^{2}$
$= 264 c m^{2}$

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A closed circular cylinder has radius equal to 3 cm and height 11cm. Find its total surface area.

Total surface area of a cylinder with a base radius 'r' and height 'h' is given by=T.S.A=2πr(h+r)For r=3cm,h=11cmT.S.A=2π(3)(11+3)=2×π7×3×14=12×22cm2=264cm2

A closed circular cylinder has radius equal to $3$ cm and height $11$ cm. Find its total surface area.

Total surface area of a cylinder with a base radius 'r' and height 'h' is given by $= T . S . A = 2 π r (h + r)$
For $r = 3 c m, h = 11 c m$
$T . S . A = 2 π (3) (11 + 3)$
$= 2 \times \frac{π}{7} \times 3 \times 14$
$= 12 \times 22 c m^{2}$
$= 264 c m^{2}$