A closed container contains equal number of moles of two gases X and Y at a total pressure of 710mm of Hg. If gas X is removed from the mixture, the pressure will :
A
become double
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B
become half
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C
remain same
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D
become one-fourth
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Solution
The correct option is B become half
Here in the closed container, the equal number of moles of two gases are taken.
Thus, when gas X is removed, the number of moles of the gases in the container becomes half.
According to an Ideal gas equation,
PV=nRT.
∴P∝n
Thus, if all the other conditions are kept constant, the pressure is directly proportional to the number of moles.
Thus, if the number of moles of the gas is halved, the pressure will also become half of the original pressure.