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Question

# A closed container has a gas A at a pressure of 200 mm of Hg at 300 K. When the container is heated to 600 K, A starts decomposing via first order kinetics as, A(g)→3B(g)+2C(g) After 1 hour and 20 minutes, the total pressure of the gaseous mixture is 1900 mm of Hg. What is the half-life of the reaction (in min) at 600 K?

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Solution

## At 300 K, the initial pressure of A is 200 mmHg At 600 K, the initial pressure of A would be twice as the temperatue is doubled, that is, 400 mmHg A(g)→3B(g)+2C(g) At, t = 0 400 0 0 At, t = 80 min 400-p 3p 2p Total pressure at 80 mins = 1900 mmHg 400 + 4p = 1900 mm of Hg Therefore, p = 375 mm of Hg Pressure of A at 600 K, 400 - 375 = 25 mm of Hg For 400 mm of Hg to become 25 mm of Hg, four half-lives should have passed. Therefore, half-life= time taken4 =804= 20 mins

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