wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A closed container is filled with 20 moles of an ideal diatomic gas at absolute temperature T. When heat is supplied to it, the temperature remains constant, but 8 moles of the gas dissociate into atoms. The heat energy supplied to the gas is

A
7RT
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6RT
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4RT
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5RT
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 4RT
Initial internal energy,
Ui=nfRT2=20×5×RT2=50RT
[for diatomic gas, f=5]

Final internal energy,
Uf=n1f1RT2+n2f2RT2
Uf=12×5×RT2+2×8×3×RT2=54RT
[if one mole of diatomic gas dissociates, then two moles of monatomic gas are produced, and for monoatomic gas, f=3]

Now, change in internal energy will be,
ΔU=UfUi=54RT50RT=4RT
Since there is no volume change associated with the process, work done W=0
Hence, heat supplied Q=ΔU=4RT
[from first law of thermodynamics]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon