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Standard XII

Physics

Ideal Gas Equation

A closed copp...

Question

A closed copper vessel contains water equal to half of its volume when the temperature. Of the vessel is raised to 447 $^{0}$ c the pressure of steam in the vessel is (Treat steam as an ideal gas, R=8310 J/k / mole, density of water =1000 kg/m $^{3}$ molecular weight of water =18 )

33.24 x 10

^{7}

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16.62 x 10

^{7}

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10.31 x 10

^{7}

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8.31x 10

^{7}

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Solution

The correct option is B 16.62 x 10 $^{7}$ pa
Let V be the volume of the copper vessel.
Then considering steam as an ideal gas,
$P V = n R T = \frac{m}{M} R T$
Mass of the water in the vessel= $m = ρ (\frac{V}{2})$
$⟹ P V = \frac{ρ V}{2 M} R T$

$⟹ P = \frac{ρ R T}{2 M} = 16.62 \times 10^{7} P a$

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A closed copper vessel contains water equal to half of its volume when the temperature. Of the vessel is raised to 4470c the pressure of steam in the vessel is (Treat steam as an ideal gas, R=8310 J/k / mole, density of water =1000 kg/m3 molecular weight of water =18 )

The correct option is B 16.62 x 107 paLet V be the volume of the copper vessel.Then considering steam as an ideal gas, PV=nRT=mMRTMass of the water in the vessel=m=ρ(V2)⟹PV=ρV2MRT⟹P=ρRT2M=16.62×107Pa

A closed copper vessel contains water equal to half of its volume when the temperature. Of the vessel is raised to 447 $^{0}$ c the pressure of steam in the vessel is (Treat steam as an ideal gas, R=8310 J/k / mole, density of water =1000 kg/m $^{3}$ molecular weight of water =18 )