A closed cubical box is completely filled with water and is accelerated horizontally towards right with an acceleration a.The resultant normal force by the water on the top of the box.
A
Passes through the centre of the top
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B
Passes through a point to the right of the centre
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C
Passes through a point to the left of the centre
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D
Becomes zero
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Solution
The correct option is C Passes through a point to the left of the centre Due to the acceleration a towards the right, a pseudo force ma acts on the water towards left. The pressure due to this force increases from right to left and the normal pressure on the top of the box by the water will vary as shown colored in the figure below. The pressure due to the gravitation on the top is zero. The total force (N) of this triangular pressure distribution will act at 1/3rd distance from the left side of the triangle. So, N will pass through a point left of the center at the top of the box.