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Question

A closed cubical box is completely filled with water and is accelerated horizontally towards right with an acceleration α. The resultant normal force by the water on the top of the box.
Consider the situation of the problem. Let the water push the left wall by a force F1 and the right wall by a force F2.

A
F1=F2
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B
F1>F2
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C
F1<F2
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D
The information is insufficient to know the relation between F1 and F2
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Solution

The correct option is B F1>F2
Explanation:

  • In the above figure, F1 and F2 forces are pushed by water on left and right wall respectively.
  • Though the motion of water is in horizontally and forward direction, the pseudo force will be in opposite direction.
  • Hence the net force on left wall is equal to summation of F1 and the pseudo force ma where m is the mass of water. i.e
  • (F1+ma) which means that force on left wall is greater than the force on the right wall. So the answer is F1>F2.



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