A closed iron tank $12 m$ long, $9 m$ wide and $4 m$ deep is to be made. Determine the cost of iron sheet used at the rate $R s . 5$ per metre sheet, sheet being $2 m$ wide.

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Solution

$T o t a l s u r f a c e a r e a o f t a n k = 2 (l b + b h + h l) = 2 (12 \times 9 + 9 \times 4 + 4 \times 12) = 2 (108 + 36 + 48) = 192 \times 2 = 384 m^{2}$

$l e n g t h o f s h e e t r e q u i r e d = \frac{a r e a}{b r e a d t h} = \frac{384}{2} = 192 m$

$N o w c o s t o f s h e e t = 192 \times 5 = R s . 960$

Hence, this is the answer.

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A closed iron tank 12 m long, 9 m wide and 4m deep is to be made. Determine the cost of iron sheet used at the rate Rs. 5 per metre sheet, sheet being 2 m wide.

Totalsurfaceareaoftank=2(lb+bh+hl)=2(12×9+9×4+4×12)=2(108+36+48)=192×2=384m2lengthofsheetrequired=areabreadth=3842=192 mNowcostofsheet=192×5=Rs. 960Hence, this is the answer.

A closed iron tank $12 m$ long, $9 m$ wide and $4 m$ deep is to be made. Determine the cost of iron sheet used at the rate $R s . 5$ per metre sheet, sheet being $2 m$ wide.