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Standing Waves in Closed Organ Pipe

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Question

A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = $340 m s^{- 1}$

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Solution

According to the Questions, V=340 m/s, n =500 Hz

We know that

$n = \frac{V}{4 I}$ (for closed pipe)

$\Rightarrow I = \frac{340}{4 \times 500} m = 17 c m$

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