A closed organ pipe has length l. The air in it is vibrating in 3rd overtone with maximum amplitude a. The amplitude at a distance of l/7 from the closed end of the pipe is equal to
A
a
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B
a2
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C
a√32
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D
zero
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Solution
The correct option is Aa Figure shows variation of displacement of particle in a closed organ pipe for 3rd overtone.
For third overtone l=7λ4 or λ=4l7 or λ4=l7 Hence the amplitude at P at a distance l/7 from closed end is ′a′ because there is an antinode at that point.