Question

An open pipe of length 33 cm resonates with frequency of $750\mathrm{Hz}$ if the speed of the sound is 330 m/s then this frequency is

Answer 1

Step 1: Given data:

On the basis of the given information:

The fundamental frequency (first harmonic frequency) of an open organ pipe is given by

$n_1=\frac{v}{\lambda }=\frac{v}{2l}$

where, $v=speedofsoundinair(330m/s)$

$\lambda =wavelength$

$l=lengthoforganpipe(33cm=0.33m)$

Step 2:

Therefore, $n_1=\frac{330}{(2\times 0.33)}=500Hz$

as an open pipe produces even and odd harmonics, and given frequency is $1000Hz$ it is $2$ times of the first harmonic frequency.

Therefore, it is the second harmonic frequency of the pipe.