A closed surface in the shape of a cube is placed in a uniform electric field $E$ along one of the sides of the cube as shown here. The length of the side is $l$ . The total electric flux through two faces 1 and 2 is:

zero

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- E l^{2}

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2 E l^{2}

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\frac{E l^{2}}{2}

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Solution

The correct option is A zero
Electric flux within any closed surface in region of uniform electric field is zero because the total number of electric lines of forces entering the closed surface equals that exiting the surface. Hence , total flux, $ϕ_{t o t} = ϕ_{i n} (2) + ϕ_{o u t} (1) = E l^{2} - E l^{2} = 0$

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Similar questions

A cube of side $L$ is placed in a uniform electric field, $\to E = E ˆ i$ . The net electric flux through the cube is

l

E^i

l = 0.2 m

\to E = (2.5^i - 4.2^j) N/C

l = 0.300 m

\to E = (- 5.00 N C^{- 1}) x^i + (3.00 N C^{- 1}) z^k

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