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Saturated Solution

A closed syst...

Question

A closed system containing $10^{- 2}$ M $H_{2}$ and $2 \times 10^{- 2}$ M $I_{2}$ at $450^{o}$ C is allowed to reach equilibrium and at equilibrium the $H I$ concentration is $1.8 \times 10^{- 2}$ M. Calculate $K_{C}$ at $450^{o}$ C for $H_{2} (g) + I_{2} (g) ⇌ 2 H I (g)$

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Solution

$\begin{matrix} H_{2} & + & I_{2} & ⇌ & 2 H I I n i t i a l & 10^{- 2} & 2 \times 10^{- 2} & 0 E q u i l i b r i u m & 10^{- 2} & {(2 \times 10^{- 2})}^{x} & 2 x \end{matrix}$
given, at equilibrium $[H I] = 1.8 \times 10^{- 2} M$
$k_{c} = \frac{(2 x)^{2}}{(0.02 - x) (0.01 - x)} = \frac{4 x^{2}}{x^{2} + 0.0002 - x (0.03)}$
$= \frac{0.000324}{0.000081 + 0.0002 - 0.00027}$
$∴$ equilibrium constant $k_{c} = 29.455$

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