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Byju's Answer
Standard VI
Chemistry
Saturated Solution
A closed syst...
Question
A closed system containing
10
−
2
M
H
2
and
2
×
10
−
2
M
I
2
at
450
o
C is allowed to reach equilibrium and at equilibrium the
H
I
concentration is
1.8
×
10
−
2
M. Calculate
K
C
at
450
o
C for
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
Open in App
Solution
H
2
+
I
2
⇌
2
H
I
I
n
i
t
i
a
l
10
−
2
2
×
10
−
2
0
E
q
u
i
l
i
b
r
i
u
m
10
−
2
(
2
×
10
−
2
)
x
2
x
given, at equilibrium
[
H
I
]
=
1.8
×
10
−
2
M
k
c
=
(
2
x
)
2
(
0.02
−
x
)
(
0.01
−
x
)
=
4
x
2
x
2
+
0.0002
−
x
(
0.03
)
=
0.000324
0.000081
+
0.0002
−
0.00027
∴
equilibrium constant
k
c
=
29.455
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Similar questions
Q.
The equilibrium constant for the reaction
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
is
32
at a given temperature.
The equilibrium concentration of
I
2
and
H
I
are
0.5
×
10
−
3
M
and
8
×
10
−
3
M
respectively. The equilibrium concentration of
H
2
is:
Q.
A sample of HI
(
9.30
×
10
−
3
)
mol was placed in an empty
2.00
L
container at
1000
K
.After equilibrium was reached, the concentration of
I
2
was
6.29
×
10
−
4
M
. Calculate the value of
K
C
at
1000
K
for the reaction
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
.
Q.
Calculate the concentration of
H
2
,
I
2
and
H
I
at equilibrium if
0.0400
mole of
H
I
is placed in a
1.00
L
flask at
430
o
C
.
K
c
for the reaction:
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
is
54.4
at this temperature.
Q.
The value of
K
p
for dissociation of
2
H
I
(
g
)
⟺
H
2
(
g
)
+
I
2
(
g
)
is
1.84
×
10
−
2
. If the equilibrium concentration of
H
2
is 0.4789 mol litre
−
1
, calculate the concentration of
H
I
at equilibrium.
Q.
Equilibrium constant
(
K
C
)
of
2
H
I
(
g
)
⇌
H
2
(
g
)
+
I
2
(
g
)
is
2
×
10
−
4
. What is the equilibrium concentration of
H
I
, if concentration of
H
2
(
g
)
and
I
2
(
g
)
respectively are
2.2
×
10
−
2
M
and
2.2
×
10
−
4
M
?
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