1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard VI
Chemistry
Saturated Solution
A closed syst...
Question
A closed system containing
10
−
2
M
H
2
and
2
×
10
−
2
M
I
2
at
450
o
C is allowed to reach equilibrium and at equilibrium the
H
I
concentration is
1.8
×
10
−
2
M. Calculate
K
C
at
450
o
C for
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
Open in App
Solution
H
2
+
I
2
⇌
2
H
I
I
n
i
t
i
a
l
10
−
2
2
×
10
−
2
0
E
q
u
i
l
i
b
r
i
u
m
10
−
2
(
2
×
10
−
2
)
x
2
x
given, at equilibrium
[
H
I
]
=
1.8
×
10
−
2
M
k
c
=
(
2
x
)
2
(
0.02
−
x
)
(
0.01
−
x
)
=
4
x
2
x
2
+
0.0002
−
x
(
0.03
)
=
0.000324
0.000081
+
0.0002
−
0.00027
∴
equilibrium constant
k
c
=
29.455
Suggest Corrections
0
Similar questions
Q.
The equilibrium constant for the reaction
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
is
32
at a given temperature.
The equilibrium concentration of
I
2
and
H
I
are
0.5
×
10
−
3
M
and
8
×
10
−
3
M
respectively. The equilibrium concentration of
H
2
is:
Q.
A sample of HI
(
9.30
×
10
−
3
)
mol was placed in an empty
2.00
L
container at
1000
K
.After equilibrium was reached, the concentration of
I
2
was
6.29
×
10
−
4
M
. Calculate the value of
K
C
at
1000
K
for the reaction
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
.
Q.
Calculate the concentration of
H
2
,
I
2
and
H
I
at equilibrium if
0.0400
mole of
H
I
is placed in a
1.00
L
flask at
430
o
C
.
K
c
for the reaction:
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
is
54.4
at this temperature.
Q.
The value of
K
p
for dissociation of
2
H
I
(
g
)
⟺
H
2
(
g
)
+
I
2
(
g
)
is
1.84
×
10
−
2
. If the equilibrium concentration of
H
2
is 0.4789 mol litre
−
1
, calculate the concentration of
H
I
at equilibrium.
Q.
Equilibrium constant
(
K
C
)
of
2
H
I
(
g
)
⇌
H
2
(
g
)
+
I
2
(
g
)
is
2
×
10
−
4
. What is the equilibrium concentration of
H
I
, if concentration of
H
2
(
g
)
and
I
2
(
g
)
respectively are
2.2
×
10
−
2
M
and
2.2
×
10
−
4
M
?
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Saturated solution_tackle
CHEMISTRY
Watch in App
Explore more
Saturated Solution
Standard VI Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app