A closed vessel contains 8 g of oxygen and 7 g of nitrogen. The total pressure is 10 atm at a given temperature. If now oxygen is absorbed by introducing a suiColumn absorbent the pressure of the remaining gas (in atm) will be:

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Solution

The correct option is D 5
According to the question,
Dalton's law of partial pressures that
$p = (n_{1} + n_{2}) \frac{R T}{V}$
$p_{1} = \frac{n_{1} R T}{V}$
$p_{2} = \frac{n_{1} R T}{V}$
$n_{1} = n_{2} = \frac{1}{4}$
$p_{1} = p_{2}$
$p_{1} = p_{2} = 10$
$p_{1} = 5 a t m$

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A closed vessel contains 8 g of oxygen and 7 g of nitrogen. The total pressure is 10 atm at a given temperature. If now oxygen is absorbed by introducing a suiColumn absorbent the pressure of the remaining gas (in atm) will be:

The correct option is D 5According to the question,Dalton's law of partial pressures thatp=(n1+n2)RTVp1=n1RTVp2=n1RTVn1=n2=14p1=p2p1=p2=10p1=5atm

The correct option is D 5
According to the question,
Dalton's law of partial pressures that
$p = (n_{1} + n_{2}) \frac{R T}{V}$
$p_{1} = \frac{n_{1} R T}{V}$
$p_{2} = \frac{n_{1} R T}{V}$
$n_{1} = n_{2} = \frac{1}{4}$
$p_{1} = p_{2}$
$p_{1} = p_{2} = 10$
$p_{1} = 5 a t m$