A closed vessel contains $8 g$ of oxygen and $7 g$ of nitrogen. The total pressure is $10$ atm at a given temperature. If now, oxygen is absorbed by introducing a suitable absorbent, the pressure of the remaining gas in atm will be

2

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5

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Solution

The correct option is D $5$
$P_{O_{2}} V = n_{O_{2}} R T$ ...(i)

$P_{N_{2}} V = n_{N_{2}} R T$ ...(ii)

Dividing (i) by (ii) we get

$\frac{P_{0_{2}}}{P_{N_{2}}} = \frac{n_{0_{2}}}{n_{n_{2}}} = \frac{1 / 2}{1 / 2} = 1$

5 atm is due to nitrogen and 5 atm due to oxygen. So, if we remove oxygen the pressure of remaining gas is 5 atm.

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A closed vessel contains 8 g of oxygen and 7 g of nitrogen. The total pressure is 10 atm at a given temperature. If now, oxygen is absorbed by introducing a suitable absorbent, the pressure of the remaining gas in atm will be

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