Given: Length of the solenoid is 80 cm, layer on the winding is 5, turn on each winding is 400, diameter of the solenoid is 1.8 cm , and the current carried by the solenoid is 8 A.
Magnetic field ( B ) inside the solenoid near its centre is given as,
B= μ 0 NI l
where, the permeability of free space is μ 0 ,total number of turns is N, current carried by solenoid is I , and length of the solenoid is l.
By substituting the given values in the above equation, we get,
B= 4π× 10 −7 ×5×400×8 80 cm×( 1 m 100 cm ) =2.512× 10 −2 T
Therefore, the magnetic field inside the solenoid near its centre is 2.512× 10 −2 T.