Question

A clutch has outer and inner diameter $100mm$ and $40mm$ respectively. Assuming a uniform pressure of $2MPa$ and coefficient of friction of the material is $0.4$, the torque carrying capacity of the clutch is

• A. $148Nm$
• B. $196Nm$
• C. $372Nm$
• D. $490Nm$

Answer 1

The correct option is B $196Nm$

Using uniform pressure theory torque carrying capacity of clutch is given by

$T=\frac{2}{3}\mu W\left(\frac{R^3-r^3}{R^2-r^2}\right)$

$=\frac{2}{3}\mu W(R^3-r^3)\left(\frac{W}{\pi (R^2-r^2)}\right)$

$=\frac{2}{3}\pi \mu p(R^3-r^3)$

$=\frac{2}{3}\times 3.14\times 0.4\times 2({\left(\frac{100}{2}\right)}^3-{\left(\frac{40}{2}\right)}^3)$

$=\frac{2}{3}\times 3.14\times 0.4\times 2({50}^3-{20}^3)$

$=195936Nmm=195.936Nm$