A co-axial cable which carrying equal current I in opposite direction have cross section as shown in diagram. If B1 and B2 are the magnetic field at inner and outer point of cable, then which of the following relation is correct
A
B1=0,B2=0
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B
B1≠0,B2≠0
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C
B1=0,B2≠0
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D
B1≠0,B2=0
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Solution
The correct option is DB1≠0,B2=0
Using Ampere's circuital law,
∮B⋅dl=μ0Ienc
Since both the coil carries cureent I in oppsite direction.
∴ For any point outside the conductor, Ienc=0 but for any inside point, Ienc≠0
Hence, B1≠0andB2=0
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Hence, (D) is the correct answer.