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Question

A co-axial cable which carrying equal current I in opposite direction have cross section as shown in diagram. If B1 and B2 are the magnetic field at inner and outer point of cable, then which of the following relation is correct


A
B1=0,B2=0
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B
B10,B20
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C
B1=0,B20
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D
B10,B2=0
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Solution

The correct option is D B10,B2=0
Using Ampere's circuital law,

Bdl=μ0Ienc

Since both the coil carries cureent I in oppsite direction.

For any point outside the conductor, Ienc=0 but for any inside point, Ienc0

Hence, B10 and B2=0

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (D) is the correct answer.

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