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Question

A coil 2.0 cm in diameter has 300 turns. If the coil carries a current of 10 mA and lies in a magnetic field 5×102 T, the maximum torque experienced by the coil is:

A
4.7×102 N-m
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B
4.7×104 N-m
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C
4.7×105 N-m
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D
4.7×108 N-m
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Solution

The correct option is A 4.7×102 N-m
Magnetic moment of experienced carrying loop M=niA
M=niAni(πr2)
work done
w=MB(1cosθ)=2MB
=2(niπr2)B
2×300×0.01A×3.14×0.1×0.1×5×102
ζ=0.00474.7×102N.M

1364071_1178493_ans_a20072822e634866a535496ad986c808.png

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