A coil has a resistance of 10Ω and an inductance of 0.4 henry. It is connected to an AC source of 6.5 V, 30π Hz. Find the average power consumed in the circuit.
Given R = 10 W,
L = 0.4 Henry,
E = 6.5 V,
f= 30πH2
Z = √R2+X2L
= √R2+(2πfL)2
Power = VrmsIrmscos θ
= 6.5×6.5ZRZ
= 6.5×6.5×10[√r2+(2πfL)2]2
= 6.5×6.5×10(10)2+(2π.30π.0.4)2
= 6.5×6.5×10100+576
= 6.5×6.5×10676
= 0.625 = 58 W