A coil has a resistance of 10Ω and an inductance of 0.4 henry. It is connected to an AC source of 6.5V,30πHz. Find the average power consumed in the circuit.
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Solution
R=10Ω L= 0.4 Henny E=6.5 V f=30πHz Z=√R2+X2L=√R2+(2πfL)2 Power=VrmsIrmscosϕ =6.5×6.5Z×RZ=6.5×6.5×10[√R2+(2πfL)2]2=6.5×6.5×10102(2π×30π×0.4)2=6.5×6.5×10100+576=0.625=58W