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Question

A coil has a resistance of 10Ω and an inductance of 0.4 henry. It is connected to an AC source of 6.5 V, 30π Hz. Find the average power consumed in the circuit.

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Solution

Given R = 10 W,

L = 0.4 Henry,

E = 6.5 V,

f= 30πH2

Z = R2+X2L

= R2+(2πfL)2

Power = VrmsIrmscos θ

= 6.5×6.5ZRZ

= 6.5×6.5×10[r2+(2πfL)2]2

= 6.5×6.5×10(10)2+(2π.30π.0.4)2

= 6.5×6.5×10100+576

= 6.5×6.5×10676

= 0.625 = 58 W


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