A coil has a self-inductance of 0.05 henry. Find magnitude of the emf induced in it when the current flowing through it is changing at the rate 100As−1.
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Solution
Given, self-inductance, L=0.05 Henry Rate of change of current, didt=100As−1 Let, Magnitude of e.m.f. e We know that, L=edi/dt 0.05=∣∣e100∣∣ |e|=5V