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Question

A coil has an inductance of 22π H and is joined in series with a resistance of 220 Ω. When an alternate e.m.f. of 220 V at 50 is applied to it, then watt less component of the rms current in the circuit.

A
5 ampere
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B
0.5 ampere
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C
0.7 ampere
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D
7 ampere
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Solution

The correct option is B 0.5 ampere
XL=2π×50×2.2π
XL=220 Ω
I=2200o220+j220
I=11+j(1j)(1j)=1j2
Imaginary part is watt-less component of I
I=0.5 A

976355_1074803_ans_1ebf238584114f8496dfccee4bfce312.png

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