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Question

A coil has resistance 30 Ω and inductive reactance 200 Ω at 50 Hz frequency. If an AC supply of 200 V , 100 Hz is connected across the coil, the current in the coil will be

A
6 A
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B
10 A
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C
4 A
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D
8 A
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Solution

The correct option is C 4 A
R=30 Ω ; XL=20 Ω at f=50 Hz

Inductance, L=XLω=XL2πf=202π×50=15π H

Vrms=200 V ; f=100 Hz

Irms=VrmsZ=VrmsR2+XL2=VrmsR2+(2πfL)2

Substituting the data given in the question,

Irms=200302+[2π×100×15π]2=200302+402

Irms=20050=4 A.

Hence, option (d) is the correct answer.

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