Question

A coil having 100 turns is placed in a magnitude field of 3T. The planes of the coil make an angle of 60 degrees with the field direction. If the area of the coil is 0.5m², then determine the magnetic flux linked with this coil.

Answer 1

Step 1: Given data

Number of turns in a coil, $N=100$

Magnitude field intensity, $B=3T$

Angle, $\theta ={60}^o$

Area of coil, $A=0.5m^2$

Step 2: Formula used

Magnetic flux through a coil with N turns is given by $\varphi =N\overrightarrow{B}.\overrightarrow{A}=NBA\cos \theta$ where B is the magnetic field intensity, A is the area of the coil and N is the number of turns.

Step 3: Finding the magnetic flux

Magnetic flux linked with a coil with N turns, $\varphi =N\overrightarrow{B}.\overrightarrow{A}=NBA\cos \theta$

$=100\times 3\times 0.5\times \cos 60$

$=100\times 3\times 0.5\times \frac{1}{2}=75Wb$

Hence, the magnetic flux linked with a coil of 100 turns is 75 Wb.

Step 4: Final answer

Thus the magnetic flux linked with this coil is 75 Wb.