Question

A coil having $200$ turns has a surface area $0.12m^2$. A magnetic field of strength $0.10Wb{m}^2$ linked perpendicular to this area to $0.5Wb{m}^2$ in $0.2s$. Find the average emf induced in the coil.

Answer 1

$n=200,A=0.12m^2$

$B_1=0.10wb/m^2,B_2=0.5wb/m^2$

$\Delta t=0.2$ &

$\Rightarrow$ choose rate of magnetic Field will be

$\frac{\Delta B}{\Delta t}=\frac{B_2-B_1}{\Delta t}=\frac{(0.5-0.1)wb/m^2}{0.2\sec }$

or $\frac{\Delta B}{\Delta t}=2$

$emfe=-\frac{\Delta \varphi }{\Delta t}=-\frac{\Delta \left(BA\right)}{\Delta t}=-A\times \frac{\Delta nB}{\Delta t}$

or $e=-An\frac{AB}{\Delta t}=-0.12\times 200\times 2volt$

volume is $|e|=48Volt$