A coil having n turns and resistance R- is connected with a galvanometer of resistance 4R- This combination is moved in time t seconds from a magnetic flux - 1 Weber to - 2 Weber- The induced current in the circuit is

The correct option is D n(ϕ_ 2 ϕ_ 1 ) 5Rt Total change in magnetic flux #160; Δϕ = n(ϕ_2 ϕ_1) Emf induced in the coil #160; ℰ = ΔϕΔ t ...

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Byju's Answer

Standard XII

Physics

Galvanometer

A coil having...

Question

A coil having $n$ turns and resistance $R Ω$ is connected with a galvanometer of resistance $4 R Ω$ . This combination is moved in time $t$ seconds from a magnetic flux $ϕ_{1}$ Weber to $ϕ_{2}$ Weber. The induced current in the circuit is

\frac{{ϕ_{2} - ϕ}_{1}}{5 R n t}

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- \frac{n ({ϕ_{2} - ϕ}_{1})}{5 R t}

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- \frac{({ϕ_{2} - ϕ}_{1})}{R n t}

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- \frac{n ({ϕ_{2} - ϕ}_{1})}{R t}

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Solution

The correct option is D $- \frac{n ({ϕ_{2} - ϕ}_{1})}{5 R t}$
Total change in magnetic flux $Δ ϕ = n (ϕ_{2} - ϕ_{1})$
Emf induced in the coil $E = - \frac{Δ ϕ}{Δ t}$
Equivalent resistance $R_{e q} = R + 4 R = 5 R$
Thus current induced $i = \frac{E}{R_{e q}}$ $= - \frac{Δ ϕ}{R_{e q} Δ t} = - \frac{n ({ϕ_{2} - ϕ}_{1})}{5 R t}$

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A coil having n turns and resistance RΩ is connected with a galvanometer of resistance 4RΩ. This combination is moved in time t seconds from a magnetic flux ϕ1 Weber to ϕ2 Weber. The induced current in the circuit is

The correct option is D −n(ϕ2−ϕ1)5RtTotal change in magnetic flux Δϕ=n(ϕ2−ϕ1)Emf induced in the coil E=−ΔϕΔtEquivalent resistance Req=R+4R=5RThus current induced i=EReq =−ΔϕReqΔt=−n(ϕ2−ϕ1)5Rt

A coil having $n$ turns and resistance $R Ω$ is connected with a galvanometer of resistance $4 R Ω$ . This combination is moved in time $t$ seconds from a magnetic flux $ϕ_{1}$ Weber to $ϕ_{2}$ Weber. The induced current in the circuit is