Question

A coil of 100 turn and area 5 cm^2 is placed in a magnetic field of 0.2 t. the normal to the plane of the coil makes an angle of 60 with the direction of magnetic field. the magnetic flux linked with the coil is:

• A. 0.0025 wb
• B. 0.0065 wb
• C. 0.0018 wb
• D. 0.005 wb

Answer 1

The correct option is C 0.0018 wb

A rectangular coil of wire$N=100$

Area$=A=10\times 15c{m}^2=150\times {10}^{-4}{m}^{-2}$

Current $I=2amp=2A$

Induction $=2\times {10}^{-3}wb/m^2$

$\sin \theta =\theta =90°\sin thet{a}_1=\sin 30°=\frac{1}{2}$

$T=nBIA\sin teta$\quad=100\times2\times10^{-3}\times12\times150\times10^{-4}\times\sin30°$

$=200\times {10}^{-7}\times 12\times 150\times \frac{1}{2}=1200\times {10}^{-6}\times 15=180\times {10}^{-4}=18\times {10}^{-3}=0.018N-m$