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Self Induction

A coil of 100...

Question

A coil of 100 turns carries a current of 5mA and creates a magnetic flux of $10^{- 5}$ Weber. The inductance is

A

0.2H

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B

2mH

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C

2H

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D

0.2mH

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Solution

The correct option is C 2H
Use the relation

$n ϕ = L i$
$100 \times 10^{- 5} = L \times 5 \times 10^{- 3}$
$L = 2 H$

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